A weightless rod of length 2 λ carries two equal masses 'm', one tied at lower end A and the other at the middle of the rod at B. The rod can rotate in vertical plane about a fixed horizontal axis passing through C. The rod is released from rest in horizontal position. The speed of the mass B at the instant rod, become vertical is :

Text Solution
Verified by ExpertsThe correct answer is:
C
Let v be the speed of B at lowermost position, the speed of A at lowermost position is 2v.
From conservation of energy
m (2v) 2 +
mv 2 = mg (2 λ .) + mg λ ..
Solving we get v =
..
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